Properly distinguish between open blocks which have no previous block, and pruned previous blocks.
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parent
08575c5b04
commit
ed11b94393
1 changed files with 7 additions and 5 deletions
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@ -2525,9 +2525,11 @@ public:
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tree.put ("previous", block_a.hashables.previous.to_string ());
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tree.put ("previous", block_a.hashables.previous.to_string ());
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}
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}
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auto balance (block_a.hashables.balance.number ());
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auto balance (block_a.hashables.balance.number ());
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auto previous_balance = handler.node.ledger.any.block_balance (transaction, block_a.hashables.previous);
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auto previous_balance_raw = handler.node.ledger.any.block_balance (transaction, block_a.hashables.previous);
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if (!previous_balance)
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auto previous_balance = previous_balance_raw.value_or (0);
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if (!block_a.hashables.previous.is_zero () && !previous_balance_raw.has_value ())
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{
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{
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// If previous hash is non-zero and we can't query the balance, e.g. it's pruned, we can't determine the block type
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if (raw)
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if (raw)
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{
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{
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tree.put ("subtype", "unknown");
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tree.put ("subtype", "unknown");
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@ -2537,7 +2539,7 @@ public:
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tree.put ("type", "unknown");
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tree.put ("type", "unknown");
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}
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}
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}
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}
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else if (balance < previous_balance.value ().number ())
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else if (balance < previous_balance.number ())
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{
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{
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if (should_ignore_account (block_a.hashables.link.as_account ()))
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if (should_ignore_account (block_a.hashables.link.as_account ()))
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{
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{
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@ -2553,7 +2555,7 @@ public:
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tree.put ("type", "send");
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tree.put ("type", "send");
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}
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}
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tree.put ("account", block_a.hashables.link.to_account ());
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tree.put ("account", block_a.hashables.link.to_account ());
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tree.put ("amount", (previous_balance.value ().number () - balance).convert_to<std::string> ());
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tree.put ("amount", (previous_balance.number () - balance).convert_to<std::string> ());
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}
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}
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else
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else
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{
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{
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@ -2592,7 +2594,7 @@ public:
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{
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{
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tree.put ("account", source_account.value ().to_account ());
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tree.put ("account", source_account.value ().to_account ());
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}
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}
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tree.put ("amount", (balance - previous_balance.value ().number ()).convert_to<std::string> ());
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tree.put ("amount", (balance - previous_balance.number ()).convert_to<std::string> ());
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}
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}
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}
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}
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}
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}
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